Question #73125
How many significant figures are there in the result of this question.
(4.321/2.8) x (6.9234x10 5) <-- 10 to the power of 5
(4.321/2.8) x (6.9234x10 5) <-- 10 to the power of 5
Expert's answer
We need to use the minimum number of significant figures in the answer.
4.321 has 4 significant figures, 2.8 has 2 significant figures, 6.9234∙〖10〗^5 has 5 significant figures.
Therefore, we need to use 2 significant figures in the answer:
(4.321/2.8)(6.9234∙〖10〗^5 )=1.1∙〖10〗^6.
4.321 has 4 significant figures, 2.8 has 2 significant figures, 6.9234∙〖10〗^5 has 5 significant figures.
Therefore, we need to use 2 significant figures in the answer:
(4.321/2.8)(6.9234∙〖10〗^5 )=1.1∙〖10〗^6.
