Question #73116

USING THE BINOMIAL THEROM,DEVELOP (x+h)^-1/2 to four terms TIA :)?

Expert's answer

Answer on Question #73116 – Math – Other

Question

USING THE BINOMIAL THEROM, DEVELOP (x+h)1/2(x+h)^{-1/2} to four terms TIA :)?

Solution


(x+h)1/2=x1/2+(12)x3/2h+12!(12)(32)x5/2h2++13!(12)(32)(52)x7/2h3=x1/212x3/2h+38x5/2h2516x7/2h3.\begin{array}{l} (x + h)^{-1/2} = x^{-1/2} + \left(- \frac{1}{2}\right) x^{-3/2} h + \frac{1}{2!} \left(- \frac{1}{2}\right) \left(- \frac{3}{2}\right) x^{-5/2} h^{2} + \\ + \frac{1}{3!} \left(- \frac{1}{2}\right) \left(- \frac{3}{2}\right) \left(- \frac{5}{2}\right) x^{-7/2} h^{3} = x^{-1/2} - \frac{1}{2} x^{-3/2} h + \frac{3}{8} x^{-5/2} h^{2} - \frac{5}{16} x^{-7/2} h^{3}. \end{array}


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