Question #234703
Obtain the equation of a parabola with focus (4,-6) and directrix as y=-2
1
Expert's answer
2021-09-13T00:26:20-0400

A parabola is defined as follows:

For a given point, called the focus, and a given line not through the focus, called the directrix, a parabola is the locus of points such that the distance to the focus equals the distance to the directrix.

Let P(x,y)P(x,y) be the point on the parabola. Then


(x4)2+(y+6)2=(y(2)2(x-4)^2+(y+6)^2=(y-(-2)^2

(x4)2=y212y36+y2+4y+4(x-4)^2=-y^2-12y-36+y^2+4y+4

(x4)2=8y32(x-4)^2=-8y-32

Therefore the required equation of the parabola is


(x4)2=8y32(x-4)^2=-8y-32

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