Answer to Question #234701 in Math for Johnnie

Question #234701
Establish the equation of the parabola with focus (-3,-4) and directrix 5x+6y-5=0
1
Expert's answer
2021-09-12T23:51:26-0400

A parabola is defined as follows:

For a given point, called the focus, and a given line not through the focus, called the directrix, a parabola is the locus of points such that the distance to the focus equals the distance to the directrix.

Let P(x,y)P(x,y) be the point on the parabola. Then


(x+3)2+(y+4)2=(5x+6y5)252+62(x+3)^2+(y+4)^2=\dfrac{(5x+6y-5)^2}{5^2+6^2}

61x2+366x+549+61y2+488y+97661x^2+366x+549+61y^2+488y+976

=25x2+36y2+25+60xy50x60y=25x^2+36y^2+25+60xy-50x-60y

36x260xy+25y2+416x+548y+1500=036x^2-60xy+25y^2+416x+548y+1500=0

Therefore the required equation of the parabola is


(6x5y)2+416x+548y+1500=0(6x-5y)^2+416x+548y+1500=0

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