Answer to Question #233296 in Math for Brit

Question

L^-1{(e-2s)/[s²(s-1)]}

Answer 1

$L^{-1}[\frac{e^{-2s}}{s^2(s-1)}]=L^{-1}[e^{-2s}(\frac{1}{s-1}-\frac{1}{s}-\frac{1}{s^2})]=$

$=(e^t-1-t)\theta(t-2).$