Question #233296

L-1{(e-2s)/[s2(s-1)]}


1
Expert's answer
2021-09-07T10:25:02-0400

L1[e2ss2(s1)]=L1[e2s(1s11s1s2)]=L^{-1}[\frac{e^{-2s}}{s^2(s-1)}]=L^{-1}[e^{-2s}(\frac{1}{s-1}-\frac{1}{s}-\frac{1}{s^2})]=

=(et1t)θ(t2).=(e^t-1-t)\theta(t-2).


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