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Answer to Question #10130 in Math for Manthan khorwal
Question #10130
Without actual divison prove that 2x2-6x2+3x2+3x-2 is exactly divisible by[x2-3x+2].
Expert's answer
2x2-6x2+3x2+3x-2=-x^2+3x-2=-(x^2-3x+2)& and it's obviously divisible by x2-3x+2
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Dear visitor As you can see from& our solution we've transformed initial polynom so that it contains x2-3x+2 as a factor. It's known that if polynom is factorized and contains other polynom as a factor then it is exactly divisible by this factor
I want full solution
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