Question #255932

An electronics manufacturing company has three production plants, each of which produces three different models of a particular MP3 player. The daily capacities (in thousands of units) of the three plants are shown in the table. Basic model Gold model Platinum model Plant 1 8 4 8 Plant 2 6 6 3 TUTORIAL LETTER SEMESTER 2/2021 MATHEMATICS FOR ECONOMISTS 1B MFE512S 12 Plant 3 12 4 8 The total demands are 300,000 units of the Basic model, 172,000 units of the Gold model, and 249,500 units of the Platinum model. The daily operating costs are $50,000 for plant 1, $60,000 for plant 2, and $60,000 for plant 3. How many days should each plant be operated in order to fill the total demand while keeping the operating cost at a minimum? What is the minimum cost? Use the method of the dual


1
Expert's answer
2021-10-26T17:35:41-0400

Let plant 1 be operated for xx days, plant 2 for yy days and plant 3 for zz days


The operating cost C will then be: C=50,000x+60,000y+60,000z50,000x+60,000y+60,000z


The objective is to find the minimum operating cost.


The constraints can be represented as:

8x+6y+12z300,0008x+6y+12z\ge300,000.................(I) ​


4x+6y+4z172,0004x+6y+4z≥172,000 ​ ​....................(II)


8x+3y+8z249,5008x+3y+8z≥249,500......................(III)


(I)-(II) gives:


8x+6y+12z(8x+3y+8z)300,000249,5008x+6y+12z-(8x+3y+8z)\ge300,000-249,500


3y+4z50,5003y+4z\ge50,500


(II)-(III) gives;


2(4x+6y+4z)(8x+3y+8z)2(172,000)(249,500)2(4x+6y+4z)-(8x+3y+8z)\ge2(172,000)-(249,500)


9y94,5009y\ge94,500


y10,500\therefore y\ge10,500


Substitute in 3y+4z50,5003y+4z\ge50,500


3(10,500)+4z50,5003(10,500)+4z\ge50,500


4z40,000z10,0004z\ge40,000 \therefore z\ge10,000


Substituting yy and zz in (I) gives;

8x+6y+12z300,0008x+6y+12z\ge300,000


8x+6(10,500)+12300,0008x+6(10,500)+12≥300,000


8x117,0008x\ge117,000


x14,625x\ge14,625


Thus x=14,625x=14,625 days

y=10,500y=10,500 days

z=10,000z=10,000 days

These values will meet the full demand and at the same time keep the operating costs at a minimum as plants will be fully utilized.


Minimum cost C=50,000(14,625)+10,500(60,000)+10,000(60,000)=$\$ 1,961,250,000




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS