Question #249769

2.3 Solve the following linear programming graphically [5]

Minimize š‘§ = 3š‘„ + 9š‘¦

Subject to the constraints: š‘„ + 3š‘¦ ≄ 6

š‘„ + š‘¦ ≤ 10

š‘„ ≤ š‘¦

š‘„ ≄ 0; š‘¦ ≄ 0


Expert's answer

Minimize š‘§=3š‘„+9š‘¦š‘§ = 3š‘„ + 9š‘¦

subject to the constraints


x+3y≄6x+y≤10x≤yx≄0,y≄0\begin{matrix} x+3y\geq6 \\ x+y \leq 10 \\ x \leq y \\ x\geq0, y\geq0 \end{matrix}

Find the point(s) of intersection


y=āˆ’13x+2y=-\dfrac{1}{3}x+2

y=āˆ’x+10y=-x+10

x=0:x=0:


y=āˆ’13(0)+2,Point A(0,2)y=-\dfrac{1}{3}(0)+2, Point\ A(0,2)

y=āˆ’0+10,Point B(0,10)y=-0+10, Point\ B(0,10)

āˆ’13x+2=x-\dfrac{1}{3}x+2=x

43x=2\dfrac{4}{3}x=2

x=1.5,y=1.5,Point D(1.5,1.5)x=1.5, y=1.5,Point\ D(1.5,1.5)


āˆ’x+10=x-x+10=x

2x=102x=10

x=5,y=5,Point C(5,5)x=5, y=5,Point\ C(5,5)


Point A(0,2):š‘§(0,2)=3(0)+9(2)=18A(0,2):š‘§(0,2) =3(0) + 9(2)=18


Point B(0,10):š‘§(0,10)=3(0)+9(10)=90B(0,10):š‘§(0,10) = 3(0) +9(10)=90


Point C(5,5):š‘§(5,5)=3(5)+9(5)=60C(5,5):š‘§(5,5) = 3(5) +9(5)=60


Point D(1.5,1.5):š‘§(1.5,1.5)=3(1.5)+9(1.5)=18D(1.5,1.5):š‘§(1.5,1.5) = 3(1.5) +9(1.5)=18


The function zz has a minimum with value of 1818 at (0,2)(0,2) and at 1.5,1.5).1.5,1.5).


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