A company is involved in the production of two items (X and Y). The resources need to produce X and Y are twofold, namely machine time for automatic processing and craftsman time for hand finishing. The table below gives the number of minutes required for each item:
Machine time Craftsman time Item
X 13 20
Y 19 29
The company has 40 hours of machine time available in the next working week but only 35 hours of craftsman time. Machine time is costed at £10 per hour worked and craftsman time is costed at £2 per hour worked. Both machine and craftsman idle times incur no costs. The revenue received for each item produced (all production is sold) is £20 for X and £30 for Y. The company has a specific contract to produce 10 items of X per week for a particular customer. Formulate the problem of deciding how much to produce per week as a linear program. Solve this linear program graphically.
Let š„ be the number of items of š, š¦ be the number of items of š. Then the LP is maximise
20š„ + 30š¦ ā 10(šššāššš š”ššš š¤ššššš) ā 2(ššššš”š ššš š”ššš š¤ššššš)
subject to:
13š„ + 19š¦ā¤ 40(60) šššāššš š”ššš
20š„ + 29š¦ā¤ 35(60) ššššš”š ššš š”ššš
š„ ā„ 10 šššš”šššš”
š„,š¦ā„ 0
so that the objective function becomes maximise
20š„ + 30š¦ ā10(13š„ + 19š¦)
60 ā2(20š„ + 29š¦)
60
i.e. maximise
17.1667š„ + 25.8667š¦
subject to:
13š„ + 19š¦ā¤ 2400
20š„ + 29š¦ā¤ 2100
š„ ā„ 10
š„,š¦ā„ 0
It is plain from the diagram below that the maximum occurs at the intersection of š„ =10 and
20š„ + 29š¦ā¤ 2100.
Solving simultaneously, rather than by reading values off the graph, we have that š„ =10 and š¦=65.52
with the value of the objective function being £1866.5.