Question #237050

A company is involved in the production of two items (X and Y). The resources need to produce X and Y are twofold, namely machine time for automatic processing and craftsman time for hand finishing. The table below gives the number of minutes required for each item:

Machine time Craftsman time Item

X 13 20

Y 19 29

The company has 40 hours of machine time available in the next working week but only 35 hours of craftsman time. Machine time is costed at £10 per hour worked and craftsman time is costed at £2 per hour worked. Both machine and craftsman idle times incur no costs. The revenue received for each item produced (all production is sold) is £20 for X and £30 for Y. The company has a specific contract to produce 10 items of X per week for a particular customer. Formulate the problem of deciding how much to produce per week as a linear program. Solve this linear program graphically.


Expert's answer



Let š‘„ be the number of items of š‘‹, š‘¦ be the number of items of š‘Œ. Then the LP is maximise

20š‘„ + 30š‘¦ āˆ’ 10(š‘šš‘Žš‘ā„Žš‘–š‘›š‘’ š‘”š‘–š‘šš‘’ š‘¤š‘œš‘Ÿš‘˜š‘’š‘‘) āˆ’ 2(š‘š‘Ÿš‘Žš‘“š‘”š‘ š‘šš‘Žš‘› š‘”š‘–š‘šš‘’ š‘¤š‘œš‘Ÿš‘˜š‘’š‘‘)

subject to:

13š‘„ + 19š‘¦ā‰¤ 40(60) š‘šš‘Žš‘ā„Žš‘–š‘›š‘’ š‘”š‘–š‘šš‘’

20š‘„ + 29š‘¦ā‰¤ 35(60) š‘š‘Ÿš‘Žš‘“š‘”š‘ š‘šš‘Žš‘› š‘”š‘–š‘šš‘’

š‘„ ≄ 10 š‘š‘œš‘›š‘”š‘Ÿš‘Žš‘š‘”

š‘„,š‘¦ā‰„ 0

so that the objective function becomes maximise

20š‘„ + 30š‘¦ āˆ’10(13š‘„ + 19š‘¦)

60 āˆ’2(20š‘„ + 29š‘¦)

60

i.e. maximise

17.1667š‘„ + 25.8667š‘¦

subject to:

13š‘„ + 19š‘¦ā‰¤ 2400

20š‘„ + 29š‘¦ā‰¤ 2100

š‘„ ≄ 10

š‘„,š‘¦ā‰„ 0

It is plain from the diagram below that the maximum occurs at the intersection of š‘„ =10 and

20š‘„ + 29š‘¦ā‰¤ 2100.

Solving simultaneously, rather than by reading values off the graph, we have that š‘„ =10 and š‘¦=65.52

with the value of the objective function being £1866.5.





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