Use simplex method to maximize 𝑓 = 3𝑥 + 5𝑦 + 4𝑧 subject to the conditions 2𝑥 + 3𝑦 ≤ 18 2𝑥 + 5𝑦 ≤ 10 3𝑥 + 2𝑦 + 4𝑧 ≤ 15 and 𝑥, 𝑦, 𝑧 ≥ 0.
Solution:
Assuming given variables x,y,z as x1, x2, x3 respectively.
Max Z=3x1+5x2+4x3
subject to
2x1+3x2≤18
2x1+5x2≤10
3x1+2x2+4x3≤15 and
x1,x2,x3≥0;
The problem is converted to canonical form by adding slack, surplus, and artificial variables as appropriate
1. As the constraint-1 is of type '≤' we should add slack variable S1
2. As the constraint-2 is of type '≤' we should add slack variable S2
3. As the constraint-3 is of type '≤' we should add slack variable S3
After introducing slack variables
Max Z=3x1+5x2+4x3+0S1+0S2+0S3
subject to
2x1+3x2+S1=18
2x1+5x2+S2=10
3x1+2x2+4x3+S3=15 and
x1,x2,x3,S1,S2,S3≥0
Similarly, going further, we get the third iteration:
Since all Zj-Cj≥0
Hence, optimal solution is arrived with value of variables as :
x1=0,x2=2,x3=2.75
Max Z=21
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