Question #193502

This time, our immune system is the best defense. With this, a Melagail wishes to mix two types of foods in such a way that vitamin contents of the mixture contain at least 8 units of vitamin A and 10 units of vitamin C. Food A contains 2 units/kg of vitamin A and 1 unit/kg of vitamin C. Food B contains 1 unit/kg of vitamin A and 2 units/kg of vitamin C. It costs ₱50 per kg to purchase Food A and ₱70 per kg to purchase Food B. Formulate this problem as a linear programming problem to minimize the cost of such a mixture.

A. Define the decision variables

B. Write the LP Model

C. Determine the feasible region

D. Determine the optimal solution

E. Final Answer: (interpret the result)


1
Expert's answer
2021-05-17T08:15:39-0400

(A) Let the mixture contains x kg of food A and y kg of Food B.


B) For vitamin A-

      Food A contains 2 unit and food B contains 1 units and total unit is at least 8.

      2x+y8\Rightarrow 2x+y\ge 8


  For Vitamin C-

        Food A contains 1 unit and food B contains 2 units and total unit is at least 10.


        x+2y10\Rightarrow x+2y\ge 10


 Also cost of food A is 50 and cost of food B is 70 per kg


  Total cost is 50x+70y


     Z=50x+70y\Rightarrow Z=50x+70y


  LP model is-

    minimize Z=50x+70yZ=50x+70y


  Subject to-

   2x+y8x+2y10and x,y0.2x+y\ge 8\\x+2y\ge10\\ \text{and } x,y\ge 0.


(c)The feasible region is shown in figure below-


 (D) On solving the above equation 

    we get the corner points (0,8),(2,4) and (10,0) 


  At (0,8)Z=0+70(8)=560(0,8)\Rightarrow Z=0+70(8)=560


  At (2,4)Z=50(2)+70(4)=100+280=380(min)(2,4)\Rightarrow Z=50(2)+70(4)=100+280=380(min)


  At (10,0)Z=50(10)+0=500(10,0)\Rightarrow Z=50(10)+0=500


Optimal solution is x=2,y=4x=2,y=4 and minimum Z=380Z=380


(E) Hence Minimum cost is 380. and mixture has 2 kg of food A and 4kg of food B.


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