Question #181433

The manager of a grocery store in the retirement community of Kapiri is interested in providing good service to the senior citizens who shop in his store. Presently, the store has a separate check-out counter for senior citizens. On average, 30 senior citizens per hour arrive at the counter according to a Poisson distribution and are served at an average rate of 35 customers per hour with exponential service times. Find the following;

(a) Utilization of the checkout clerk

(b) Number of customers in a system

(c) Number of customers in line

(d) Time spent in the system

(e) Waiting time in line

The manager of Kapiri grocery wants to answer the following question:

(1) What service rate would be required to have customers average only eight minutes in


1
Expert's answer
2021-05-03T08:32:24-0400

We have given,

L = Average arrival time = λ\lambda = 30 per hour

M = Average service rate = μ\mu = 35 per hour

a.) Utilization of the checkout clerk, U=LMU = \dfrac{L}{M} = 3035\dfrac{30}{35} = 85.785.7 % %

b.) Number of customers in a system,

Firstly we have to find out the Average number of customers or units waiting in line for service

Lq=λ2μ(μλ)L_q = \dfrac{\lambda^2}{\mu(\mu-\lambda)}


=30×3035(3530)= \dfrac{30\times 30}{35(35-30)}


Lq=5.14L_q= 5.14 ,


Now, Average number of customers or units in the system = Lq+λμL_q + \dfrac{\lambda}{\mu}


= 5.14+30355.14+\dfrac{30}{35}

=5.997= 5.997

c.) Number of customers in a line =Lq=5.14= L_q = 5.14

d.) Time spent in the system

But before that we have to find out,

The Average time a customer or unit spends waiting in line for service Wq=LqλW_q = \dfrac{L_q}{\lambda}

Hence, Wq=5.1430=0.17W_q = \dfrac{5.14}{30} = 0.17

Now, time spent in the system W=Wq+1μW = W_q + \dfrac{1}{\mu}


= 0.17+1350.17 + \dfrac{1}{35}


=0.19= 0.19

e.) Waiting time in line =Wq=0.17= W_q = 0.17


1.) Service rate would be required to have customers average only eight minutes in = 608×35=262.5\dfrac{60}{8} \times 35 = 262.5


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