Use Simplex method to
Maximize Ζ = 4x + 10x2
Subject 2X+X2 ≤ 50
2X + 5X2 ≤ 100
2X + 3X2 ≤ 100
X, X2 ≥ 0
"Max Z=4x_1+10x_2\\\\subject\\ to\\\\2x_1+x_2\u226450\\\\2x_1+5x_2\u2264100\\\\2x_1+3x_2\u2264100\\\\and\\ \\ x_1,x_2\u22650;"
The problem is converted to canonical form by adding slack, surplus and artificial variables as appropriate
1. As the constraint-1 is of type '≤' we should add slack variable S1
2. As the constraint-2 is of type '≤' we should add slack variable S2
3. As the constraint-3 is of type '≤' we should add slack variable S3
After introducing slack variables
"Max Z=4x_1+10x_2+0S_1+0S_2+0S_3\\\\subject\\ to\\\\2x_1+x_2+S_1=50\\\\2x_1+5x_2+S_2=100\\\\2x_1+3x_2+S_3=100\\\\and \\ x1,x2,S1,S2,S3\u22650"
Negative minimum"Z_j-C_j" is -10 and its column index is 2. So, the entering variable is "x_2" .
Minimum ratio is 20 and its row index is 2. So, the leaving basis variable is "S_2" .
∴ The pivot element is 5.
Entering ="x_2" , Departing ="S_2" , Key Element =5
Since all "Z_j-C_j\u22650"
Hence, optimal solution is arrived with value of variables as :
"x_1=0,x_2=20"
Max Z = 200
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