Prove that, if S is square, U is unitary, and U^(conjugate transpose)SU = T is upper triangular, then the eigenvalues of S and T are the same and S and T have the same trace. (Use the facts that det(AB) = det(A)det(B), and tr(ABC) = tr(CAB) = tr(BCA)).
Shur's Lemma: For any square matrix S therer is a unitary matrix U such that
U^(conjugate transpose)SU = T is an upper triangular matrix.
Use Shur's Lemma to prove that
(a) If S^(conjugate transpose)=S then there is a unitary matrix U such that U^(conjugate transpose)SU is a real diagonal matrix.
(b) If S is real and and S^T = S then there is an orthogonal matrix O such that O^TSO is a real diagonal matrix.
Associated with each equation (Ax)_i=b_i in the system Ax=b there is a hyperplane H_i defined to be the subset of J-dimensional column vectors given by: H_i = {x|(Ax)_i = b_i}.
Show that, for any vector z in C^J, the member of H_i closest to z is x having the entries
Associated with each equation (Ax)_i=b_i in the system Ax=b there is a hyperplane H_i defined to be the subset of J-dimensional column vectors given by:
H_i = {x|(Ax)_i=b_i}.
Show that the ith column of A^(conjugate transpose) is normal to the hyperplane H_i; that is, it is orthogonal to every vector lying in H_i.
Ok so I have 3 matrix' and its A B C and I have to solve (-1 means inverse) for (A-1xB)-1xC so does (A inverse times B) the whole thing inverse times C = (B-1A)C?
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