Question #27355

write the matrix A[3,-1,1,-2]as a linear combination of A1=[1,1,0,-1],A2=[1,1,-1,0]and A3=[1,-1,0,0]

Expert's answer

Write the matrix A=[3,1,1,2]A = [3, -1, 1, -2] as a linear combination of A1=[1,1,0,1]A1 = [1, 1, 0, -1], A2=[1,1,1,0]A2 = [1, 1, -1, 0] and A3=[1,1,0,0]A3 = [1, -1, 0, 0]

**Solution:**

We need to present the matrix AA in the form:


A=xA1+yA2+zA3A = x * A_1 + y * A_2 + z * A_3


where x,y,zx, y, z some constants.


xA1+yA2+zA3=x[1,1,0,1]+y[1,1,1,0]+z[1,1,0,0]=[x,x,0,x]+[y,y,y,0]+[z,z,0,0]=[x+y+z,x+yz,0y+0,x+0+0]=[x+y+z,x+yz,y,x]\begin{array}{l} x * A_1 + y * A_2 + z * A_3 = x * [1, 1, 0, -1] + y * [1, 1, -1, 0] + z * [1, -1, 0, 0] \\ = [x, x, 0, -x] + [y, y, -y, 0] + [z, -z, 0, 0] \\ = [x + y + z, x + y - z, 0 - y + 0, -x + 0 + 0] \\ = [x + y + z, x + y - z, -y, -x] \end{array}


So we have that


[x+y+z,x+yz,y,x]=A[x + y + z, x + y - z, -y, -x] = A[x+y+z,x+yz,y,x]=[3,1,1,2][x + y + z, x + y - z, -y, -x] = [3, -1, 1, -2]


We have next system of linear equation:


{x+y+z=3x+yz=1y=1x=2\left\{ \begin{array}{l} x + y + z = 3 \\ x + y - z = -1 \\ -y = 1 \\ -x = -2 \end{array} \right.{2z=4y=1x=2\left\{ \begin{array}{l} 2z = 4 \\ y = -1 \\ x = 2 \end{array} \right.{x=2y=1z=2\left\{ \begin{array}{l} x = 2 \\ y = -1 \\ z = 2 \end{array} \right.


So matrix AA can be present as


A=2A1A2+2A3A = 2A_1 - A_2 + 2A_3


**Answer:** A=2A1A2+2A3A = 2A_1 - A_2 + 2A_3

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS