Write the matrix A=[3,−1,1,−2] as a linear combination of A1=[1,1,0,−1], A2=[1,1,−1,0] and A3=[1,−1,0,0]
**Solution:**
We need to present the matrix A in the form:
A=x∗A1+y∗A2+z∗A3
where x,y,z some constants.
x∗A1+y∗A2+z∗A3=x∗[1,1,0,−1]+y∗[1,1,−1,0]+z∗[1,−1,0,0]=[x,x,0,−x]+[y,y,−y,0]+[z,−z,0,0]=[x+y+z,x+y−z,0−y+0,−x+0+0]=[x+y+z,x+y−z,−y,−x]
So we have that
[x+y+z,x+y−z,−y,−x]=A[x+y+z,x+y−z,−y,−x]=[3,−1,1,−2]
We have next system of linear equation:
⎩⎨⎧x+y+z=3x+y−z=−1−y=1−x=−2⎩⎨⎧2z=4y=−1x=2⎩⎨⎧x=2y=−1z=2
So matrix A can be present as
A=2A1−A2+2A3
**Answer:** A=2A1−A2+2A3