Question #324959

Let W = {(x, y, z): y² = x + z}, Is W a subspace of R³

1
Expert's answer
2022-04-07T12:08:59-0400

WW consists of all vectors (x,y,z)(x,y,z) satisfying: y2=x+zy^2=x+z. Suppose that (x1,y1,z1)(x_1,y_1,z_1) and (x2,y2,z2)(x_2,y _2,z_2) belong to WW. It means that y12=x1+z1y_1^2=x_1+z_1 and y22=x2+z2y_2^2=x_2+z_2. But, it does not mean that (x1+x2,y1+y2,z1+z2)(x_1+x_2,y_1+y_2,z_1+z_2) belongs to WW. I.e., it may not satisfy (y1+y2)2=(x1+x2)+(z1+z2)(y_1+y_2)^2=(x_1+x_2)+(z_1+z_2). For example, we can choose (1,2,3)(1,2,3) and (0,1,1)(0,1,1). It is clear that both vectors belong to WW. But (1,3,4)(1,3,4) does not belong to WW, since 321+43^2\neq1+4. The latter means that one of subspace properties is not satisfied for WW . Therefore, it is not a subspace of R3\mathbb{R}^3 .


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