Consider the linear equation 2a + 3b = 4
Is (a; b) = (1; 1
2
) a solution to the equation? Motivate your answer.
If (a,b)=(1,12),(a, b)=(1,\dfrac{1}{2}),(a,b)=(1,21), then substitute
Therefore (a,b)=(1,12)(a, b)=(1, \dfrac{1}{2})(a,b)=(1,21) is not a solution to the equation 2a+3b=1.2a+3b=1.2a+3b=1.
If (a,b)=(12,1),(a, b)=(\dfrac{1}{2}, 1),(a,b)=(21,1), then substitute
Therefore (a,b)=(12,1)(a, b)=(\dfrac{1}{2}, 1)(a,b)=(21,1) is a solution to the equation 2a+3b=1.2a+3b=1.2a+3b=1.
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