Let W={(x,y,z)∣x+y+z=0}.
a) Taking into account that
W={(x,y,z)∣x+y+z=0}={(x,y,−x−y)∣x,y∈R}={x(1,0,−1)+y(0,1−1)∣x,y∈R},
we conclude that the vectors (1,0,−1) and (0,1,−1) form a basis for W.
b) Since two vectors form a basis for W, the dimension of W is equal to 2.
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