Question #258094

Let W={(x,y,z)|x+y+z=0}

a, give a basis for W

b, what is the dimension of W


Expert's answer

Let W={(x,y,z)∣x+y+z=0}.W=\{(x,y,z)|x+y+z=0\}.


a) Taking into account that


W={(x,y,z)∣x+y+z=0}={(x,y,−x−y)∣x,y∈R}={x(1,0,−1)+y(0,1−1)∣x,y∈R},W=\{(x,y,z)|x+y+z=0\}=\{(x,y,-x-y)|x,y\in\R\}\\=\{x(1,0,-1)+y(0,1-1)|x,y\in\R\},


we conclude that the vectors (1,0,−1)(1,0,-1) and (0,1,−1)(0,1,-1) form a basis for W.W.


b) Since two vectors form a basis for W,W, the dimension of WW is equal to 2.



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