Question #258094

Let W={(x,y,z)|x+y+z=0}

a, give a basis for W

b, what is the dimension of W


1
Expert's answer
2021-11-01T17:39:42-0400

Let W={(x,y,z)x+y+z=0}.W=\{(x,y,z)|x+y+z=0\}.


a) Taking into account that


W={(x,y,z)x+y+z=0}={(x,y,xy)x,yR}={x(1,0,1)+y(0,11)x,yR},W=\{(x,y,z)|x+y+z=0\}=\{(x,y,-x-y)|x,y\in\R\}\\=\{x(1,0,-1)+y(0,1-1)|x,y\in\R\},


we conclude that the vectors (1,0,1)(1,0,-1) and (0,1,1)(0,1,-1) form a basis for W.W.


b) Since two vectors form a basis for W,W, the dimension of WW is equal to 2.



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