Prove that every finite dimensional vector space has a basis.
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Expert's answer
2013-02-05T11:36:22-0500
Let W be nonzero finitedimensional space. We can find some nonzero u1 in W. Then space W1=(WSpan(u1))U{0} is again finite dimensional vector space. If it is nonzero, then we can implement the above construction and gain u2, that is linearly independent to u1. By mathematical induction, w can continue the process, until we get Wn={0}, and it always occurs as W was finite dimensional. So, the constructed above set u1,u2,...,un forms a linearly independent set and is maximal with this property, so it is a basis.
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