The diagonals of a square bisect each other and meet at 90°. Therefore, the coordinates of crossing-point of the diagonals coincide with the coordinates of bisection point of GO, which can be found via averaging of coordinates of points G and O
and equal (-1,0).
The diagonals of a square are equal, so projection of GO to X axis must be equal to projection of EM to Y axis and vice versa.
Hence, the coordinates of E are (-1 - "\\frac{GO_y}{2}" ,0 - "\\frac{GO_x}{2}" ),
where "GO_y" - the projection of GO to Y axis, that equals 4,
"GO_x" - the projection of GO to X axis, that equals 6.
So, coordinates of E are (-3,-3).
The coordinates of M are (-1 + "\\frac{GO_y}{2}" , 0 + "\\frac{GO_x}{2}").
So, coordinates of M are (1,3).
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