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Answer to Question #56876 in Geometry for samagra
Question #56876
Determine all values of α for which the point (α, α²) lies inside the triangle formed by the lines 2x + 3y − 1 = 0 ; x + 2y − 3 = 0 ; 5x − 6y − 1 = 0.
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Comments
Dear samagra. Points inside the triangle lie above the graphs of y=-2x/3+1/3, y=5x/6-1/6 (that is, 2x+3y-1=0, 5x-6y-1=0) and lie below the graph of y=-x/2+3/2 (that is, x+2y-3=0). Algebraically it can be expressed as y>-2x/3+1/3, y>5x/6-1/6, y0, 5x-6y-1
Sir why we have taken the inequality
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