Find the lateral area and volume of the frustum of a right circular cone having a slant height of 14m and the radii of the bases are 4m and 1.5 m respectively.
The lateral area of the frustum of a right circular cone is equal to one-half of the sum of the circumferences of the bases multiplied by slant height
"=\\pi(R+r)l=\\pi(4+1.5)(14)(m^2)=77\\pi\\ m^2"
The frustum volume is
"h=\\sqrt{l^2-(r-r)^2}=\\sqrt{14^2-(4-1.5)^2}(m)"
"=\\dfrac{\\sqrt{759}}{2}(m)"
"V=\\dfrac{1}{3}\\pi (\\dfrac{\\sqrt{759}}{2})(4^2+1.5^2+4(1.5))(m^3)"
"=\\dfrac{97\\sqrt{759}}{24}\\pi (m^3)"
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