Find the height of a trapezoid with area of 99m2
and the bottom base is twice the top base,
Calculation
99 m2=12(6 m+3 m)h99×2=2×12×(9)×h99×2×19=19×9hh=2\qquad\qquad \begin{aligned} \small 99\,m^2&=\small \frac{1}{2}(6\,m+3\,m)h\\ \small 99\times2&=\small \cancel{2}\times\frac{1}{\cancel{2}}\times(9)\times h\\ \small 99\times2\times\frac{1}{9}&=\small\frac{1}{\cancel{9}}\times \cancel{9}h\\ \small h &=\small 2 \end{aligned}99m299×299×2×91h=21(6m+3m)h=2×21×(9)×h=91×9h=2
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