Given a soda can with a volume of 36 and a diameter of 4, what is the volume of a cone that fits perfectly inside the soda can? (Hint: only enter numerals in the answer blank).
"Solution: For ~this~ case ~what~ we~ should~ do~ is~ model~ the ~soda ~can ~as~ a ~cylinder.\n\\\\We have then:\n\\\\V=\\pi r^2 h\n\\\\Where,\n\\\\r: radius ~ of ~the ~can\n\\\\h: height ~of ~the ~can\n\\\\From ~`here, we ~clear~ the ~value ~of ~the ~height:\n\\\\Substituting ~values~ we~ have:\n\\\\We~ are~ now~ looking~ for~ the~ volume ~of ~the ~cone.\n\\\\We ~have~ then:\n\\\\V=\\frac{1}{3} \\pi r^2 h\n\\\\Substituting~values~we~have:\n\\\\V=\\frac{1}{3} \\pi (2^2) (2.87)=12.02 \\approx 12\n\\\\Answer:The~volume ~of~ a ~cone~ that~ fits~ perfectly~ inside~ the~ soda~ can~ is ~V=12"
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