You are interesting in a buying a gift that is shaped like a cube for your fruend.However,you only have a 5 square yards of wrapping paper.the formula is s=√A-6 where s is the edge length,and A is the surface area.What is the longest side length of a cube you could buy based on how much wrapping paper you have?round your answer to the nearest tenth of a yard?
"\\displaystyle\ns = \\sqrt{\\frac{A}{6}} \\\\\ns^2 =\\frac{A}{6} \\\\\nA = 6s^2 \\\\\n\n6s^2 \\leq 5 \\\\\n\n6s^2 - 5 \\leq 0\\\\\n\ns^2 - \\frac{5}{6} \\leq 0 \\\\\n\n\\left(s - \\sqrt{\\frac{5}{6}}\\right)\\left(s - \\sqrt{\\frac{5}{6}}\\right) \\leq 0 \\\\\n\n-\\sqrt{\\frac{5}{6}} \\leq s \\leq \\sqrt{\\frac{5}{6}} \\\\\n\n\\therefore \\textsf{The longest side length of a cube you}\\\\\n\\textsf{could buy based on how much wrapping}\\\\\n\\textsf{paper you have is}\\,\\,\\, 0.9\\,\\,\\textsf{yards}\\,\\, (\\textsf{to nearest tenth})."
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