Consider the cylindrical silo with hemispherical top as shown in the figure below:
The total volume of the silo is,
"V=\\pi (6^2)(40)+\\frac{2}{3} \\pi (6^3)"
"=1440\\pi+144\\pi"
"=1584\\pi"
The amount of grain put into the silo is,
"A=1584\\pi(\\frac{80}{100})"
"=1267.20\\pi"
The number of truckloads to fill to silo to its recommended capacity of 80% is,
"n=\\frac{1267.20\\pi}{(8)(4)(3.5)}"
"=\\frac{396}{35}\\pi"
"\\approx 36"
Therefore, the number of truckloads to fill the silo to its recommended capacity is "n\\approx36"
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