Answer to Question #149222 in Geometry for marshy taray

Question

4. The areas of the bases of a frustum of a regular pyramid is 250 m2 and 640 m2 respectively. Find the altitude of the pyramid if the altitude of its frustum is 130 m?

Answer 1

$A .S.F=\frac{640}{250}$

This implies that $A.S.F=\frac{64}{25}$

$L.S.F= \sqrt{\frac{64}{25}}$

Therefore, $L.S.F=\frac{8}{5}$

$\frac{X+130}{X}=\frac{8}{5}$

Solving for X,

$5X+650=8X$

$3X=650$

$X=216.67m$

Therefore, the altitude of the pyramid is: $X+130=346.67m$