Answer to Question #132532 in Geometry for Mark

Question #132532
If RS=44 and QS=68, Find QR

Find the distance between the point (1,4) and (-2,-1)

Find the midpoint of segment with endpoints (9,8) and (3,5)

ABC is right Triangle AB =

Find the distance between the points (1,-8)and(-7,-2)
1
Expert's answer
2020-09-10T17:25:16-0400

If RS=44 and QS=68, Find QR

  1. Line QS is a continuation of line RS: QR=QS+QR=68+44=112QR = QS + QR = 68 + 44 = 112
  2. Point R belongs to line QS: QR=QSRS=6844=24QR = QS - RS = 68 - 44 = 24



Find the distance between the point (1,4) and (-2,-1):

Distance =(21)2+(14)2=(3)2+(5)2=(9+25)=34\sqrt{( -2 - 1)^2 + (-1 - 4)^2} = \sqrt{(-3)^2 + (-5)^2} = \sqrt{(9 + 25)} = \sqrt{34}


Find the midpoint of segment with endpoints (9,8) and (3,5):

Midpoint(xc, yc):

xc=xa+xb2=9+32=122=6,yc=ya+yb2=5+82=132=6.5x_c = \dfrac{x_a + x_b}{2} = \dfrac{9 + 3}{2} = \dfrac{12}{2} = 6 , y_c = \dfrac{y_a + y_b}{2} = \dfrac{5 + 8}{2} = \dfrac{13}{2} = 6.5

Midpoint(6, 6.5)


ABC is right Triangle AB =

Pythagorean theorem AB=BC2+AC2AB = \sqrt{BC^2 + AC^2} (ifС=90°)( if \angleС = 90\degree)


Find the distance between the points (1,-8)and(-7,-2):

Distance =(71)2+(2(8))2=(8)2+(2+8)2=(8)2+(6)2=(64+36)=100=10\sqrt{( -7 - 1)^2 + (-2 - (-8))^2} = \sqrt{(-8)^2 + (-2 + 8)^2} = \sqrt{(-8)^2 + (6)^2} = \sqrt{(64 + 36)} = \sqrt{100} = 10

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Comments

Assignment Expert
15.10.20, 21:40

Dear Jade, please use the panel for submitting new questions.

Jade
15.10.20, 17:43

If RS =32.5 and QS= 62.1 find QR

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