Question #103117
the distance between the center of symmetry of a paralleglogram and its longer side
1
Expert's answer
2020-02-17T10:41:31-0500


Consider the parallelogram ABCD. Assume that we know its longest diagonal d1d_1and the distance between A and K, which is b according to the figure. Therefore, we can use the Pythagorean theorem.

Consider the right triangle based on the point O where the diagonals cross, points A and K. Its hypotenuse is half of the longest diagonal, catheti are the unknown distance and AK:


(d1/2)2=x2+AK2,d12/4=x2+AK2,d12/4AK2=x2,x=d12/4AK2.(d_1/2)^2=x^2+AK^2,\\ d_1^2/4=x^2+AK^2,\\ d^2_1/4-AK^2=x^2, \\x=\sqrt{d^2_1/4-AK^2}.


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