The equation of the lane passing through A and B is "-7x + 3y = -21.5"
this could be written as "y=\\dfrac{7x}{3}-\\dfrac{21.5}{3}"
slope of this line is 7/3
central street PQ will be perpendicular to the lane passing through A and B
slope of central street PQ = "\\dfrac{-1}{slope \\ of\\ lane \\ joining \\ A\\ and \\ B}=\\dfrac{-1}{7\/3}=\\dfrac{-3}{7}"
Equation of the central street PQ .
"y=mx+c"
"y=-3x\/7 \\ +c"
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