Question

what is the solution of a triangular pennant is to be made with a base of 3 dm and a height of 4dm. It is to be cut from a square piece of cloth with a side of 4 dm, what is the area of a pennant? of the square piece of cloth? how much material will be left?

Answer 1

S_LKC=1/2LC*DC

S_LKC=1/2*3*4=6dm² (pennant area)

S_ABCD=(DC)²

S_ABCD=4²=16dm² (square area a piece of cloth)

S_ABLK+S_CKD= 16dm²-6dm²=10dm² (material which will be left after cutting).