$10000 was compounded annually at 12.5% p.a. and amounted to $52015.80. How many years did it take?
"A=P(1+r)^t"
"52015.80=10000(1+0.125)^t"
"5.201580=[1+0.125]^t"
"5.201580=[1.125]^t"
"log5.201580=tlog(1.125)"
"t=\\frac{log5.201580}{log1.125}=14years"
Comments
Leave a comment