How much is to be invested now at 10% compound interest p.a. if after 5 years the investment is to reach a target sum of $30000.
"A=P(1+\\frac {r} {100}) ^n"
"30,000=P(1 +0.1)^5"
"30000=(1.1)^5 P"
"1.6105P=30,000"
"P=\\$18,627.76"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment