Question #254765
Jane plans to retire in 30 years and would like to have $500,000 in her account. If the interest on her account is 3.92% compounded monthly, how much should she put into her account every month? A. 1,633.33 B. 1,388.89 C. 730.74 D. 653.33 Which would result in the need for a larger monthly deposit to a retirement account with the same ending balance? A. Half the number of years before the money is withdrawn from the account B. Half the interest rate
1
Expert's answer
2021-10-25T15:19:26-0400

A=P[(1+rn)nt1]rnA=\frac{P[(1+\frac{r}{n})^{nt}-1]}{\frac{r}{n}}

A== $ 500,000

P=?=?

r== 3.921200\frac{3.92}{1200} Compounded monthly

n== 12

t== 30 years


500,000=P[(1+3.921200)12×301]3.921200500,000=\frac{P[(1+\frac{3.92}{1200})^{12×30}-1]}{\frac{3.92}{1200}}

500,000=684.24P500,000=684.24P

P=730.74P=730.74

Half of the years we will use 15 years:

500,000=P[(1+3.921200)12×151]3.921200500,000=\frac{P[(1+\frac{3.92}{1200})^{12×15}-1]}{\frac{3.92}{1200}}

500,000=244.49P500,000=244.49P

P=2045.09P=2045.09

For half the interest we use 1.96% so:

500,000=P[(1+1.961200)12×301]1.961200500,000=\frac{P[(1+\frac{1.96}{1200})^{12×30}-1]}{\frac{1.96}{1200}}

500,000=489.50P500,000=489.50P

P=1021.45

Half the number of years will result in a larger monthly deposit of 2045.09

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