A=16250−16250×0.075+311=15342.25A=16250-16250\times0.075+311=15342.25A=16250−16250×0.075+311=15342.25
B=927+1156=2083
pay month class A:
P=S(i+i(1+i)n−1)P=S(i+\frac{i}{(1+i)^n-1})P=S(i+(1+i)n−1i)
P=15342.25(0.02+0.02(1+0.02)12−1)=1450.76P=15342.25(0.02+\frac{0.02}{(1+0.02)^{12}-1})=1450.76P=15342.25(0.02+(1+0.02)12−10.02)=1450.76
paying of class B;
S=2083
P=150
n=logSPlog(1+i)n=\frac{log\frac{S}{P}}{log(1+i)}n=log(1+i)logPS
n=log2083165log(1+0.18)=log12.624242log1.18=1.1010.07188=15.3n=\frac{log\frac{2083}{165}}{log(1+0.18)}=\frac{log12.624242}{log1.18}=\frac{1.101}{ 0.07188}=15.3n=log(1+0.18)log1652083=log1.18log12.624242=0.071881.101=15.3
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