A savings account pays interest at the rate of 5% per year, compounded semi-annually. The amount that should be deposited now so that R250 can be withdrawn at the end of every six months for the next ten years is
[1] R3 144,47.
[2] R6 386,16.
[3] R1 930,43.
[4] R3 897,29.
[5] none of the above
Given Amount to be withdrawn every six months is R250 = x
Rate of interest, i = 5%
For six months , i = (5/2)% = 2.5% = 0.025
Given Time, n = 10
For six months, n = 10*2 = 20
We know that present value of series of payments is P = x[1-(1+i)-n]/i
Now P = 250[1-(1+0.025)-20]/0.025
P = 250[1-0.61]/0.025
P = 250(0.39)/0.025
P = 250*15.589
P = R3897.291
Thus, R3897.29 should be deposited so that R250 can be withdrawn at the end of every six months for the next ten years.
So, option 4 is correct.
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