An amount borrowed at 29% interest per year, compounded continuously, has accumulated to R38 279,20 after four years. The initial amount borrowed was
[1] R13 823,05.
[2] R12 000,00.
[3] R12 005,53.
[4] R17 721,85.
[5] R7 160,73.
"Future \\space value=Amount\\times e^{rt}"
"3827920=Amount\\times e^{0.29\\times 4}"
"3827920=Amount\\times 3.189933"
"\\frac{3827920}{3.189933}=Amount"
"Amount=1200000.022"
"Amount=1200000"
[2] R12 000,00. is correct option.
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