An amount borrowed at 29% interest per year, compounded continuously, has accumulated to R38 279,20 after four years. The initial amount borrowed was
[1] R13 823,05.
[2] R12 000,00.
[3] R12 005,53.
[4] R17 721,85.
[5] R7 160,73.
Future value=Amount×ertFuture \space value=Amount\times e^{rt}Future value=Amount×ert
3827920=Amount×e0.29×43827920=Amount\times e^{0.29\times 4}3827920=Amount×e0.29×4
3827920=Amount×3.1899333827920=Amount\times 3.1899333827920=Amount×3.189933
38279203.189933=Amount\frac{3827920}{3.189933}=Amount3.1899333827920=Amount
Amount=1200000.022Amount=1200000.022Amount=1200000.022
Amount=1200000Amount=1200000Amount=1200000
[2] R12 000,00. is correct option.
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