Consider the following series: 5 + 8 + 11 + 14 +...+164
1.1.1 Calculate the number of terms in the series. (3)
1.1.2 Calculate the sum of the series. (3)
1.1.3 Express the series in sigma notation.
1.1.1 Calculate the number of terms in the series.
nth term=a+(n-1)d
where
a is 1st term,
n is the number of terms,
d is the common difference;
a=5;
d=14-11=11-8=8-5=3;
164=5+(n-1)3
159=3n-3
162=3n
n=54
1.1.2 Calculate the sum of the series.
sn=n/2 [2a+(n-1)d]
where;
sn is the sum of n terms in the series,
a is 1st term,
d is the common difference.
s54=54/2 [10+(54-1)3]
s54=27[10+53×3]
s54=27×169
s54=4563
1.1.3 Express the series in sigma notation.
"\\displaystyle\\sum_{n=1}^{54}(3n+2)"
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