Question #350181

Show that the square of an even number is an even number using a direct proof.



1
Expert's answer
2022-06-13T14:30:50-0400

Given nn is even. Then kZ\exist k\in \Z such that n=2k.n=2k.

Then


n2=(2k)2=4k2=2(2k2)n^2=(2k)^2=4k^2=2(2k^2)

Let m=2k2,kZ.m=2k^2, k\in \Z. Then m=2k2,mZ.m=2k^2, m\in \Z.

So n2=2m,mZ.n^2=2m, m\in \Z. This means that n2n^2 is even.

Therefore the square of an even number is an even number.


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