Show that the square of an even number is an even number using a direct proof.
Given nnn is even. Then ∃k∈Z\exist k\in \Z∃k∈Z such that n=2k.n=2k.n=2k.
Then
Let m=2k2,k∈Z.m=2k^2, k\in \Z.m=2k2,k∈Z. Then m=2k2,m∈Z.m=2k^2, m\in \Z.m=2k2,m∈Z.
So n2=2m,m∈Z.n^2=2m, m\in \Z.n2=2m,m∈Z. This means that n2n^2n2 is even.
Therefore the square of an even number is an even number.
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