Question #336459

Find the inverse function of (x+1)/x

1
Expert's answer
2022-05-03T07:50:10-0400

The domain of the function f(x)=x+1xf(x)=\frac{x+1}{x} consists of all real numbers except of . I.e., the domain is: (,0)(0,+)(-\infty,0)\cup(0,+\infty). In order to find the inverse, we need to solve the equation: z=x+1xz=\frac{x+1}{x}. We get: zx=x+1zx=x+1. We receive: x=1z1x=\frac{1}{z-1}. The domain of the inverse function is: (,1)(1,+)(-\infty,1)\cup(1,+\infty)

Answer: the inverse function is: 1z1\frac{1}{z-1}.


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