Let R1 and R2 be two relation on real number such that R1 = {(x, y)|x < y} and R2 =
{(x, y)|x > y}, then find R1 ∪ R2,R1 ∩ R2,R1 − R2, R2 − R1, and R1+LR2.
R1 R2={(x,y)|x>y or x<y}={(x,y)|x!=y}
R1 R2={(x,y)|x>y and x<y}=
R1-R2=R1-R1 R2=R1 -{(x,y)|x>y and x<y}=R1-=R1
R2-R1=R2-R1 R2=R2 -{(x,y)|x>y and x<y}=R2-=R2
R1+LR2=R1 LR2-R1 LR2={(х,у)}-∅={(x,y) }
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