Answer to Question #306671 in Discrete Mathematics for ibrahim

Question #306671

(S∪T)∘R= (S∘R)∪(T∘R).


1
Expert's answer
2022-03-07T17:04:03-0500

Solution


For the three sets, A,BA, B , and CC , We define


RR a relation from AA to AA B.


SS and TT are two relations from BB to CC

 

Now for both, (ST)R(S ∪ T) ∘ R and (SR)(TR)(S ∘ R) ∪ (T ∘ R)


(ST)R(S ∪ T) ∘ R is the subset of A×CA × C


And (SR)(TR)(S ∘ R) ∪ (T ∘ R) is the subset of A×CA × C


Therefore, for any arbitrary element (u,v)(ST)R(u, v) ∈ (S ∪ T) ∘ R


Then there is vBv ∈ B , such that (u,v)R(u, v) ∈ R and (u,v)(ST)(u, v) ∈ (S ∪ T)


Therefore, (u,v)S(u, v) ∈ S and (u,v)T(u, v) ∈ T


Hence, (u,v)(ST)(u, v) ∈ (S ∪ T)


Similarly, we can prove, (u,v)(TR)(u, v) ∈ (T ◦ R)


Therefore, We can write


(ST)R=(SR)(TR)(S ∪ T) ∘ R = (S ∘ R) ∪ (T ∘ R)


Hence Proved


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