(S∪T)∘R= (S∘R)∪(T∘R).
Solution
For the three sets, "A, B" , and "C" , We define
"R" a relation from "A" to "A" B.
"S" and "T" are two relations from "B" to "C"
Now for both, "(S \u222a T) \u2218 R" and "(S \u2218 R) \u222a (T \u2218 R)"
"(S \u222a T) \u2218 R" is the subset of "A \u00d7 C"
And "(S \u2218 R) \u222a (T \u2218 R)" is the subset of "A \u00d7 C"
Therefore, for any arbitrary element "(u, v) \u2208 (S \u222a T) \u2218 R"
Then there is "v \u2208 B" , such that "(u, v) \u2208 R" and "(u, v) \u2208 (S \u222a T)"
Therefore, "(u, v) \u2208 S" and "(u, v) \u2208 T"
Hence, "(u, v) \u2208 (S \u222a T)"
Similarly, we can prove, "(u, v) \u2208 (T \u25e6 R)"
Therefore, We can write
"(S \u222a T) \u2218 R = (S \u2218 R) \u222a (T \u2218 R)"
Hence Proved
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