The discriminant of the equation 3x2−x−55=0 is equal to D=1+3⋅4⋅55=661, and hence the equation has the solutions x1=61−661≈−4.11 and x2=61+661≈4.45
It follows that the real solutions of the inequlity 3x2−x<55 belong to the set (61−661,61+661).
This set contains the following natural numbers: 1,2,3,4.
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