1. List all elements in A. A={xϵN:(3x2-x)<55}
Let us list all elements in "A=\\{x\\in\\N:(3x^2-x)<55\\}."
For this let us solve the inequality "3x^2-x<55."
The discriminant of the equation "3x^2-x-55=0" is equal to "D=1+3\\cdot4\\cdot 55=661," and hence the equation has the solutions "x_1=\\frac{1-\\sqrt{661}}{6}\\approx -4.11" and "x_2=\\frac{1+\\sqrt{661}}{6}\\approx 4.45"
It follows that the real solutions of the inequlity "3x^2-x<55" belong to the set "(\\frac{1-\\sqrt{661}}{6},\\frac{1+\\sqrt{661}}{6})."
This set contains the following natural numbers: "1,2,3,4."
Consequently, "A=\\{1,2,3,4\\}."
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