Answer to Question #286778 in Discrete Mathematics for Riya

Question #286778

State TRUE or FALSE justifying your answer with proper reason.



a. 2𝑛^2 + 1 = 𝑂(𝑛^2 )



b. 𝑛^2 (1 + βˆšπ‘›) = 𝑂(𝑛^2 )



c. 𝑛^2 (1 + βˆšπ‘›) = 𝑂(𝑛^2 log 𝑛)



d. 3𝑛^2 + βˆšπ‘› = 𝑂(𝑛 + π‘›βˆšπ‘› + βˆšπ‘›)



e. βˆšπ‘› log 𝑛 = 𝑂(𝑛)

1
Expert's answer
2022-01-24T16:13:54-0500

a.

True

2𝑛2+1≀3n22𝑛^2 + 1\le 3n^2


b.

False

lim⁑nβ†’βˆžπ‘›2(1+𝑛)n2=∞\displaystyle \lim_{n\to \infin} \frac{𝑛^2 (1 + \sqrt𝑛) }{n^2}=\infin


c.

False

lim⁑nβ†’βˆžπ‘›2(1+𝑛)n2logn=∞\displaystyle \lim_{n\to \infin} \frac{𝑛^2 (1 + \sqrt𝑛) }{n^2logn}=\infin


d.

False

lim⁑nβ†’βˆž3𝑛2+𝑛)𝑛+𝑛𝑛+𝑛=∞\displaystyle \lim_{n\to \infin} \frac{ 3𝑛^2 + \sqrt𝑛) }{𝑛 + 𝑛\sqrt𝑛 + \sqrt𝑛}=\infin


e.

True

𝑛log𝑛≀n\sqrt𝑛 log 𝑛\le n

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