Answer to Question #284619 in Discrete Mathematics for Abdullah

Question #284619

Justify whether the given operations on relevant sets are binary operations or not.




- Multiplication and Division on set of natural numbers



- Subtraction and Addition on Set of natural numbers



- Exponential operation: (x, y) → xy on Set of Natural numbers and set of Integers.


1
Expert's answer
2022-01-04T17:53:21-0500

Solution:

1.

Basically, binary operations on a set are calculations that combine two elements of the set (called operands) to produce another element of the same set.

The binary operation, (say *) on a non-empty set A are functions from A × A to A.

"*: A \u00d7 A \u2192 A"

It is an operation of two elements of the set whose domains and co-domain are in the same set.

Closure property: An operation * on a non-empty set A has closure property, if,

"a \u2208 A, b \u2208 A \u21d2 a * b \u2208 A"


2.

i)

Multiplication of two natural numbers is always a natural number.

Division of two natural numbers may not always be a natural number, it may result in fractions(rational numbers). e.g.: "2 \\in N, 3 \\in N, but (2\/3)\\notin N"

Thus, Multiplication is a binary operation on the set of Natural numbers whereas Division is not a binary operation on the set.

ii)

Addition of two natural numbers is always a natural number.

Subtraction of two natural numbers does not need always to be a natural number, the result can be negative(integer). e.g.: "2 \\in N, 3 \\in N, but (2-3)=-1\\notin N"

iii)

Exponential operation on two natural numbers always results in a natural number.

However, exponential operation on two integers does not always result in an integer.

eg: "2,3 \\in Z; 2^3=8\\in Z". But "2, -3 \\in Z; 2^{-3}=1\/8=0.125 \\notin Z"

Thus, exponentiation is a binary operation on the set of Natural numbers whereas it is not a binary operation on the set of Integers.


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