Answer to Question #283009 in Discrete Mathematics for Cutie

Question

There are 10 stalls for animals in an exhibition. Three animals; lion, pussycat

and horse are to be exhibited. Animals of each kind are not less than 10 in

number. What is the possible number of ways of arranging the exhibition?

Answer 1

For each stall there are 3 ways to exhibit one of three animals. Since there are 10 stalls, by Combinatorial Product Rule, the number of ways of arranging the exhibition is equal to $3\cdot 3\cdot\ldots\cdot 3=3^{10}=59,049.$