If x and y are not both even numbers, then neither the square of x and y is odd, nor the cube of x and y is even
Answer: false
for example, if x is even and y is odd numbers, then:
x=2k1x=2k_1x=2k1
y=2k2+1y=2k_2+1y=2k2+1
where k1, k2 = 0,1,2,3,...
(x+y)2=(2k1+2k2+1)2(x+y)^2=(2k_1+2k_2+1)^2(x+y)2=(2k1+2k2+1)2 is odd
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