Ask about the lenght of 5 formed using the lettre ABCDEFG without repetitions. How many string begins with the letter F and end with the letter A
It follows that that by Combinatorial Product Rule the number of strings of length 5 which consist of the letters A, B, C, D, E, F and G without repetition is equal to "7\\cdot6\\cdot 5\\cdot4\\cdot 3=2,520." The number of strings of length 5 without repetition which begins with the letter F and end with the letter A is equal to "5\\cdot 4\\cdot 3=60."
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