Solution.
"f(x)=x^3,f:R\\to R"
Let x1,x2 ∈R and let us assume f(x1)=f(x2).
So, "x_1^3=x_2^3\\implies x_1=x_2."
Hence, we have f(x1)=f(x2)
implies x1=x2.
So, f is one-one (injective).
Also we know
So, we clearly observe the Co-Domain is the same as the Range, so f(x) is surjective.
And hence f(x) is bijective.
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