d.
n=C63=6!3!3!=20n=C^3_6=\frac{6!}{3!3!}=20n=C63=3!3!6!=20 ways
e.
n=2C52=2⋅5!2!3!=20n=2C^2_5=\frac{2\cdot5!}{2!3!}=20n=2C52=2!3!2⋅5!=20 ways
f.
n=C52=5!2!3!=10n=C^2_5=\frac{5!}{2!3!}=10n=C52=2!3!5!=10 ways
g.
n=C41=4!3!=4n=C^1_4=\frac{4!}{3!}=4n=C41=3!4!=4 ways
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